200=15x^2

Solution for 200=15x^2 equation:

200=15x^2

We move all terms to the left:

200-(15x^2)=0

a = -15; b = 0; c = +200;
Δ = b2-4ac
Δ = 02-4·(-15)·200
Δ = 12000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12000}=\sqrt{400*30}=\sqrt{400}*\sqrt{30}=20\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{30}}{2*-15}=\frac{0-20\sqrt{30}}{-30}
=-\frac{20\sqrt{30}}{-30}
=-\frac{2\sqrt{30}}{-3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{30}}{2*-15}=\frac{0+20\sqrt{30}}{-30}
=\frac{20\sqrt{30}}{-30}
=\frac{2\sqrt{30}}{-3}
$